3x^2-6x-252=0

Solution for 3x^2-6x-252=0 equation:

3x^2-6x-252=0

a = 3; b = -6; c = -252;
Δ = b2-4ac
Δ = -62-4·3·(-252)
Δ = 3060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3060}=\sqrt{36*85}=\sqrt{36}*\sqrt{85}=6\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{85}}{2*3}=\frac{6-6\sqrt{85}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{85}}{2*3}=\frac{6+6\sqrt{85}}{6}
$